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Question

A bullet is fired into a block of wood sitting on a block if ice. The bullet has an initail velocity of 500m/s and a mass of 0.005 kg. The wooden block has a mass of 2kg and is initially at rest. The bullet remains embedded in the block of wood afterward. a. Assuming that the momentum is conserved, find the final velocity of the block of wood (and bullet) after the collision. b. What is the magnitude of the impulse that acts on the block of wood in this process? c. Does the change in momentum of the bullet equal that of the block of wood? Explain thoroughly.

Solution

x. xxxxxxx Momentum = Final xxxxxxxx xx* xx = (xx+ mw) * xx xx = xx* vb / (xx+ xx) vf = 1.247 x/x x. impulse = mb (xx-xx) = x.xxx kg x/x x. xx, xxxxxxxx is x vector xxxxxxy. xxxy xxx equal xx magnitude, xxx xx xxxxxxxx directions.

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A bullet is fired into a block of wood sitting on a block if ice. The bullet has an initail velocity of 500m/s and a mass of 0.005 kg. The wooden block has a mass of 2kg and is initially at rest. The bullet remains embedded in the block of wood afterward. a. Assuming that the momentum is conserved, find the final velocity of the block of wood (and bullet) after the collision. b. What is the magnitude of the impulse that acts on the block of wood in this process? c. Does the change in momentum of the bullet equal that of the block of wood? Explain thoroughly.
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